Implement a list using rust.
Rust果然比較複雜,在經歷了n次compile fail,終于寫成了一個 list
難點: 對Rc<>的用法不熟悉。對borrow checker不夠熟悉
有些寫法可能還不是最短的
use std::rc::Rc;
fn main() {
println!("Hello, world!");
let li = ListInternal {
data: 1,
next: None,
};
let li = ListInternal {
data: 2,
next: Some(Rc::new(li)),
};
let mut l = List { next: Some(li) };
for i in 1..10{
l.push_back(i);
}
l.print();
}
struct ListInternal {
data: i32,
next: Option<Rc<ListInternal>>,
}
struct List {
next: Option<ListInternal>,
}
impl ListInternal {
fn print(&self) {
println!("{}", self.data);
if let Some(ref v) = self.next {
v.print();
}
}
fn print_loop(&self) {
let mut t = self;
loop {
println!("{}", t.data);
if let Some(ref v) = t.next {
t = v;
} else {
break;
}
}
}
fn last(&mut self) -> &mut Self {
let mut t = self;
loop {
if let Some(ref mut v) = t.next {
t = Rc::get_mut(v).unwrap();
} else {
break;
}
}
t
}
}
impl List {
fn new() -> List {
List { next: None }
}
fn print(&self) {
if let Some(ref v) = self.next {
v.print_loop();
}
}
fn push_back(&mut self, data: i32) {
let li = ListInternal {
data: data,
next: None,
};
if let Some(ref mut v) = self.next {
v.last().next = Some(Rc::new(li));
} else {
self.next = Some(li);
}
}
}
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